Polynomials – SS2 Further Mathematics Lesson Note (First Term)
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- Subject
- Further Mathematics
- Class
- SS2
- Term
- First Term
- Topic
- Polynomials
- Order
- Topic 3 of 6 this term
- Reading time
- 4 min
A polynomial is an expression made from non-negative whole-number powers of a variable x, multiplied by numerical constants and added together.
Behavioural objectives
By the end of the lesson, students should be able to:
- write the general form of a polynomial and name its coefficients, constant term and degree;
- name a polynomial by its degree (constant, linear, quadratic, cubic or quartic);
- identify expressions that are polynomials and expressions that are not;
- state the condition for two polynomials to be equal;
- add and subtract polynomials.
What is a polynomial?
A polynomial in x is an expression in which every power of x is a non-negative whole number, usually written p(x) or P(x).
The general polynomial has this form:
P(x) = anxn + an-1xn-1 + … + a2x² + a1x + a0
Here an, an-1, …, a0 are numerical constants and an ≠ 0.
What are the parts of a polynomial?
- Variable: the letter x, which can take different values.
- Term: each part joined by + or -, such as 3x² or -2x.
- Coefficient: the constant that multiplies a power of x. In 3x² – 2x + 4, the coefficient of x² is 3 and of x is -2.
- Constant term: the term with no x, written a0. In 3x² – 2x + 4 it is 4.
- Degree: the highest power of the variable, written n in the general form. In 3x² – 2x + 4 the degree is 2.
- Leading coefficient: the coefficient of the highest power, an. It cannot be zero.
Examples of polynomials
- (a) P1(x) = 3x² – 2x + 4: degree 2.
- (b) P2(x) = 3x² – 2x² + x – 1: simplifies to x² + x – 1, so the degree is 2.
- (c) P3(x) = x + 1: degree 1.
- (d) P4(x) = 2x³ + x – 3: degree 3.
What are the types of polynomial by degree?
Polynomials are named by their degree: constant, linear, quadratic, cubic and quartic.
| Degree | Name | Example |
|---|---|---|
| 0 | Constant | 5 |
| 1 | Linear | x + 1 |
| 2 | Quadratic | 3x² – 2x + 4 |
| 3 | Cubic | 2x³ + x – 3 |
| 4 | Quartic | x⁴ – 5x² + 1 |
Which expressions are not polynomials?
An expression is not a polynomial if x has a negative power, a fractional power or appears in a denominator.
- Negative power: (2x – 3)-1, which is the same as 1/(2x – 3), is not a polynomial.
- Fractional power: (x² + 2x – 3)1/2, the square root of x² + 2x – 3, is not a polynomial.
- Variable in the denominator: (3x² – 4x² + 2x – 1)/(2x + 3) is not a polynomial.
When are two polynomials equal?
Two polynomials are equal when the coefficients of every matching power of x are equal.
Let P(x) = anxn + an-1xn-1 + … + a1x + a0 and Q(x) = bnxn + bn-1xn-1 + … + b1x + b0. Then P(x) = Q(x) provided:
an = bn, an-1 = bn-1, …, a2 = b2, a1 = b1, a0 = b0
- Missing term: a power of x that is absent has coefficient 0.
- Example: if ax² + bx + 3 = 2x² – 5x + c, then a = 2, b = -5 and c = 3.
How do we add and subtract polynomials?
To add or subtract polynomials, add or subtract the coefficients of like powers of x.
P(x) + Q(x) = (an + bn)xn + (an-1 + bn-1)xn-1 + … + (a1 + b1)x + (a0 + b0)
P(x) – Q(x) = (an – bn)xn + (an-1 – bn-1)xn-1 + … + (a1 – b1)x + (a0 – b0)
What are the steps?
- Write each polynomial in brackets, with the sign between them.
- For subtraction, change the sign of every term in the second bracket.
- Group like terms: the x³ terms, the x² terms, the x terms and the constants.
- Add the coefficients in each group.
- Write the answer from the highest power to the lowest.
- Multiplying by a constant: multiply every coefficient by that constant, so 3(2x² + x – 6) = 6x² + 3x – 18.
Worked examples
Given that P1(x) = 7x³ – 4x² + 3x + 4, P2(x) = 5x² + 6x + 1 and P3(x) = 4x³ + 2x – 3, find:
- (a) P1(x) + P2(x)
- (b) P1(x) + P3(x)
- (c) P1(x) – P2(x)
- (d) P3(x) – P2(x)
- (e) P1(x) + P2(x) + P3(x)
Solution
(a) P1(x) + P2(x)
= (7x³ – 4x² + 3x + 4) + (5x² + 6x + 1)
= 7x³ + (-4x² + 5x²) + (3x + 6x) + (4 + 1)
= 7x³ + x² + 9x + 5
(b) P1(x) + P3(x)
= (7x³ – 4x² + 3x + 4) + (4x³ + 2x – 3)
= (7x³ + 4x³) + (-4x²) + (3x + 2x) + (4 – 3)
= 11x³ – 4x² + 5x + 1
(c) P1(x) – P2(x)
= (7x³ – 4x² + 3x + 4) – (5x² + 6x + 1)
= 7x³ + (-4x² – 5x²) + (3x – 6x) + (4 – 1)
= 7x³ – 9x² – 3x + 3
(d) P3(x) – P2(x)
= (4x³ + 2x – 3) – (5x² + 6x + 1)
= 4x³ – 5x² + (2x – 6x) + (-3 – 1)
= 4x³ – 5x² – 4x – 4
(e) P1(x) + P2(x) + P3(x)
= (7x³ – 4x² + 3x + 4) + (5x² + 6x + 1) + (4x³ + 2x – 3)
= (7x³ + 4x³) + (-4x² + 5x²) + (3x + 6x + 2x) + (4 + 1 – 3)
= 11x³ + x² + 11x + 2
Evaluation
- State the degree, the constant term and the coefficient of x in 3x² – 2x + 4.
- State the condition for two polynomials P(x) and Q(x) to be equal.
- Using P2(x) and P3(x) from the worked examples, find P2(x) + P3(x).
- Using P1(x) and P3(x) from the worked examples, find P3(x) – P1(x).
- Give one reason why 1/(2x – 3) is not a polynomial.
Assignment
If p1 = 3x³ + 2x² – x + 2, p2 = 2x² + x – 6 and p3 = x³ + 3x² + 2x – 4, find:
- p1 + p2
- p3 – p2
- p2 + p3 – 3p1
- p1 + p2 + p3
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