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Number System – JSS1 Mathematics Lesson Note (Second Term)

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Lesson note at a glance

Subject
Mathematics
Class
JSS1
Term
Second Term
Topic
Number System
Order
Topic 4 of 7 this term
Reading time
2 min

Converting a number from one base to another is a two-stage process. First, change the given number to base ten, then change the result to the required base. Numbers in base two can also be added, subtracted and multiplied using simple rules for the digits 0 and 1.

Behavioural objectives

By the end of the lesson, students should be able to:

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  • convert a number from one base to another through base ten;
  • add numbers in base two;
  • subtract numbers in base two;
  • multiply numbers in base two.

How do you convert a number from one base to another?

This is a two-stage process. First, convert the given base to base ten. Then convert the result to the required base.

Example 1: Convert 21356 to a number in base two

Step one: Convert to base ten.

21356 = (2 × 63) + (1 × 62) + (3 × 61) + (5 × 60)
= (2 × 216) + (1 × 36) + (3 × 6) + (5 × 1)
= 432 + 36 + 18 + 5
= 49110

Step two: Convert the answer in base ten to a number in base two by dividing repeatedly by 2. Read the remainders from the bottom upwards.

Divide by Number Remainder
2 491
2 245 1
2 122 1
2 61 0
2 30 1
2 15 0
2 7 1
2 3 1
2 1 1
0 1

Therefore 21356 = 1111010112

Example 2: Express 101112 as a number in base three

101112 = (1 × 24) + (0 × 23) + (1 × 22) + (1 × 21) + (1 × 20)
= 1 × 16 + 0 × 8 + 1 × 4 + 1 × 2 + 1 × 1
= 16 + 0 + 4 + 2 + 1
= 2310

Now divide repeatedly by 3 and read the remainders from the bottom upwards.

Divide by Number Remainder
3 23
3 7 2
3 2 1
0 2

Therefore 101112 = 2123

How do you add and subtract in base two?

Use the following rules.

Addition in base two

  • 0 + 0 = 0
  • 1 + 0 = 1
  • 1 + 1 = 10
  • 1 + 1 + 1 = 11

Subtraction in base two

  • 0 – 0 = 0
  • 1 – 0 = 1
  • 10 – 1 = 1
  • 11 – 1 = 10

Example 3: Add the following

  1. 11012 and 11112
  2. 110112, 101012 and 10012

Solution:

(1) Using the addition rule 1 + 1 = 10, write 0 down and carry the 1 to the next column. Carry the 1 in the same way in each column until you reach the last one.

 11012
+ 11112
= 111002

(2) Add the three numbers in the same way.

 110112
 101012
+ 10012
= 1110012

Example 4: Subtract (a) 10112 from 101012 (b) 110112 from 1110102

Solution:

(a) Using the subtraction rule 1 – 1 = 0, write 0 down and move to the next column.

 101012
– 10112
= 10102

(b)

 1110102
– 110112
= 111112

How do you multiply binary numbers?

Multiply by each digit of the second number, move each row one place to the left, and then add the rows using the rules for addition in base two.

Example 5: Find the product of 10112 and 1012

Solution:

 10112
× 1012
 1011
 0000 (moved one place left)
 1011 (moved two places left)
= 1101112

Example 6: Multiply 11112 by 1102

Solution:

 11112
× 1102
 0000
 1111 (moved one place left)
 1111 (moved two places left)
= 10110102

Evaluation

  1. Add the following: (a) 10012 + 11112 (b) 1011102 + 100102
  2. Subtract 10112 from 11011012.
  3. Multiply 1101012 by 10112.
  4. Find the value of the following binary numbers: 10112 + 102 – 1112

This term's Mathematics topics

JSS1 Second Term · 7 topics

  1. Approximation
  2. Addition and Subtraction of Approximations
  3. Number Base
  4. Number System
  5. Basic Operation
  6. Addition & Subtraction of Directed Numbers
  7. Algebra Process
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