Rational and Non-Rational Numbers and Compound Interest – JSS3 Mathematics Lesson Note (Third Term)
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- Subject
- Mathematics
- Class
- JSS3
- Term
- Third Term
- Topic
- Rational and Non-Rational Numbers and Compound Interest
- Order
- Topic 8 of 12 this term
- Reading time
- 7 min
A rational number can be written as an exact fraction of two integers, while a non-rational number cannot. Compound interest is interest worked out on the principal plus the interest already earned.
Behavioural objectives
- Define rational and non-rational numbers and give examples of each.
- Find square roots of numbers that are not perfect squares using tables.
- Calculate simple interest and compound interest, and the amount, on a given sum.
- Solve problems on direct, inverse, joint and partial variation.
What are rational numbers?
A rational number is a number that can be written as the fraction p/q, where p and q are integers and q is not zero.
- Whole numbers and integers: 8 = 8/1 and 15 = 15/1.
- Fractions and mixed numbers: 3 1/2 = 7/2.
- Terminating decimals: 0.31 = 31/100 and 0.1 = 1/10.
- Recurring decimals: 17/99 = 0.171717…, 4/11 = 0.363636… and 10/3 = 3.3333…
- Square roots of perfect squares: the square root of 16/9 is 4/3.
- A recurring decimal is written with dots over the digits that repeat, for example 0.17 with dots over 1 and 7.
What are non-rational numbers?
A non-rational (irrational) number cannot be written as an exact fraction or a recurring decimal.
- Decimal form: the decimal goes on forever and never repeats.
- Square roots of non-perfect squares: √7 = 2.645751…, √17 = 4.1231056… and √29 = 5.3851648…
- Pi: π is also non-rational.
What is the difference between rational and non-rational numbers?
| Feature | Rational | Non-rational |
|---|---|---|
| As a fraction | Can be written as p/q | Cannot be written as p/q |
| Decimal form | Ends or repeats | Never ends and never repeats |
| Examples | 8, 7/2, 0.31, 0.3333… | √7, √17, √29, π |
How do you find the square root of a number that is not a perfect square?
Use the table of square roots in the four-figure tables, or use trial and error.
- If the number is between 1 and 100, read the square root straight from the table.
- If the number is larger, write it as a number between 1 and 10 multiplied by 100 (or 10 000).
- Read the square root of the small number from the table.
- Multiply by 10 (for 100) or by 100 (for 10 000).
- Round to the places or figures asked for.
Example 1
Find √17 to 3 significant figures.
- The table gives √17 = 4.123.
- Answer: 4.12 to 3 s.f.
Example 2
Find √293 to the nearest tenth.
- 293 = 2.93 × 100.
- √293 = √2.93 × √100 = 1.712 × 10 = 17.12.
- Answer: 17.1 to the nearest tenth.
What is compound interest?
Compound interest is interest calculated each year on the principal plus all the interest already added.
- Principal (P): the money borrowed or invested at the start.
- Rate (R): the percentage interest each year.
- Time (n): the number of years.
- Amount (A): the principal plus the interest.
What is simple interest?
Simple interest is interest calculated on the original principal only, every year.
- Formula: I = PRT/100, where T is the time in years.
- Example: N2,000 at 5% for 3 years gives (2000 × 5 × 3)/100 = N300.
- Amount: A = P + I.
What is the formula for compound interest?
- Amount: A = P(1 + R/100)n.
- Compound interest: C.I. = A – P.
How do you work out compound interest?
- Write down P, R and n.
- Work out 1 + R/100 as a decimal.
- Raise it to the power n.
- Multiply by P to get the amount A.
- Subtract P to get the compound interest.
Example 3: year by year
Find the compound interest on N10,000 for 2 years at 5%.
| Year | Principal (N) | Interest (N) | Amount (N) |
|---|---|---|---|
| 1 | 10,000 | 500 | 10,500 |
| 2 | 10,500 | 525 | 11,025 |
- Compound interest = 11,025 – 10,000 = N1,025.
Example 4: using the formula
Find the amount and compound interest on N5,000 for 3 years at 10%.
- A = 5000 × (1.1)3 = 5000 × 1.331 = N6,655.
- C.I. = 6,655 – 5,000 = N1,655.
What is the difference between simple and compound interest?
| Feature | Simple interest | Compound interest |
|---|---|---|
| Interest is worked on | The original principal only | Principal plus earned interest |
| Yearly interest | Stays the same | Grows each year |
| Formula | I = PRT/100 | A = P(1 + R/100)n |
What is direct variation?
Direct variation describes two quantities that increase or decrease together in the same proportion.
- Statement: P varies directly as R is written P ∝ R.
- Equation: P = kR, where k is the constant of variation.
- Constant: k = P/R.
- Graph: a straight line through the origin.
Example 5
p varies directly as the square of q, and p = 27 when q = 3. Find the law, p when q = 2, and q when p = 48.
- p = kq².
- k = 27/3² = 27/9 = 3, so the law is p = 3q².
- When q = 2: p = 3 × 4 = 12.
- When p = 48: q² = 48/3 = 16, so q = 4.
Example 6: graph of direct variation
| Time | 1 | 2 | 3 | 4 | 5 |
|---|---|---|---|---|---|
| Distance | 5 | 10 | 15 | 20 | 25 |
- Distance divided by time is always 5, so D = 5T.
- Plot time across and distance up.
- The points lie on a straight line through the origin.
What is inverse variation?
Inverse variation describes two quantities where one increases as the other decreases, so their product stays constant.
- Statement: T varies inversely as S is written T ∝ 1/S.
- Equation: T = k/S.
- Constant: k = TS.
- Graph: a curve, not a straight line.
Example 7
T is inversely proportional to S, and T = 2 when S = 60. Find the relationship and T when S = 90.
- k = TS = 2 × 60 = 120.
- The relationship is T = 120/S.
- When S = 90: T = 120/90 = 4/3 = 1 1/3.
Example 8: graph of inverse variation
| Speed | 80 | 40 | 20 | 10 | 5 |
|---|---|---|---|---|---|
| Time | 0.5 | 1 | 2 | 4 | 8 |
- Speed × time = 40 each time, so S = 40/t.
- Plotting the points gives a smooth curve that falls as time increases.
What is joint variation?
Joint variation is when a quantity varies with more than one other quantity, directly, inversely or both.
- Both direct: P ∝ QG means P = kQG.
- Direct and inverse: H ∝ Y/M means H = kY/M.
Example 9
H ∝ Y/M, and H = 42 when Y = 7 and M = 3. Find the relation, and H when Y = 5 and M = 9.
- k = HM/Y = (42 × 3)/7 = 18.
- The relation is H = 18Y/M.
- When Y = 5 and M = 9: H = (18 × 5)/9 = 10.
Example 10: universal gas law
V varies directly as T and inversely as P. At T = 425 K and P = 1000 N/m², V = 0.255 m³. Find the formula, and P when T = 720 K and V = 0.018 m³.
- V = kT/P, so k = PV/T = (1000 × 0.255)/425 = 255/425 = 3/5.
- The formula is V = 3T/(5P).
- Make P the subject: P = 3T/(5V) = (3 × 720)/(5 × 0.018) = 2160/0.09.
- P = 24,000 N/m².
What is partial variation?
Partial variation is when a quantity is made of two parts: one part is constant and the other part varies.
Everyday examples
- Hairdresser’s charge: M = C + bT, where C is the cost of the wool, T is the time taken, and C and b are constants.
- Prepaid electricity bill: B = 750 + bU, where N750 is the fixed rental charge and U is the units used.
Common forms
- Partly constant, partly varies as G: W = a + bG.
- Partly as P, partly inversely as Q: V = aP + b/Q.
- The constants a and b are found by solving two equations at the same time.
Example 11
x is partly constant and partly varies as y². x = 3 when y = 4, and x = 1 when y = 5. Find the law and x when y = 2.
- x = a + by².
- Equation (i): a + 16b = 3. Equation (ii): a + 25b = 1.
- Subtract (ii) from (i): -9b = 2, so b = -2/9.
- From (i): a = 3 + 32/9 = 59/9 = 6 5/9.
- The law is x = 59/9 – (2/9)y².
- When y = 2: x = 59/9 – 8/9 = 51/9 = 5 2/3.
Example 12
T varies partly as V and partly as V³. T = 30 when V = 2, and T = 15 when V = 3. Find the law and T when V = 4.
- T = aV + bV³.
- 30 = 2a + 8b, which gives a + 4b = 15 (i).
- 15 = 3a + 27b, which gives a + 9b = 5 (ii).
- Subtract (i) from (ii): 5b = -10, so b = -2.
- From (i): a = 15 – 4(-2) = 23.
- The law is T = 23V – 2V³.
- When V = 4: T = 92 – 128 = -36.
Example 13
The cost of making a dress is partly constant and partly varies with the hours taken. It costs N2,700 for 3 hours and N3,100 for 5 hours. Find the cost for 1 1/2 hours.
- C = a + bT.
- 2700 = a + 3b and 3100 = a + 5b.
- Subtract: 2b = 400, so b = 200.
- a = 2700 – 600 = 2100.
- The law is C = 2100 + 200T.
- When T = 1.5: C = 2100 + 300 = N2,400.
Evaluation
- Which of these is non-rational: 3/7, 0.25, √13 or 0.6666…?
- Find the square root of 7562 to one decimal place, using tables.
- Find the compound interest on N8,000 borrowed for 2 years at 20%.
- Find the simple interest and the amount on N7,000 for 4 years at 7 1/2%.
- The current I in a circuit varies inversely as the resistance R. A current of 10 A flows when R = 20 ohms. Find I when R = 80 ohms.
Assignment
Find the amount and the compound interest on N20,000 invested for 2 years at 10%, then find √5720 to one decimal place.
- Reading: Essential Mathematics for J.S.S. 3 by Oluwasanmi A.J.S. (2014 edition), pages 38-45 and 49-53.
- Practice: Essential Mathematics Workbook for J.S.S. 3, Exercise 7.1 (numbers 1-5), Exercise 7.2 (numbers 1-12) and Exercise 5.1 (numbers 6-10).
This term's Mathematics topics
JSS3 Third Term · 12 topics
- Construction
- Measures of Central Tendency
- Application of Measures of Central Tendency to Analyse Given Information
- Data Presentation: Pie Charts
- Binary Numbers: Number Base Conversions
- Solving Equation Expressions
- Binary Numbers (Base 2)
- Rational and Non-Rational Numbers and Compound Interest
- Factorisation
- Word Problems: Solving Equation Expression
- Change of Subject of Formula
- Multiplication and Division in Base 2
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