Vectors in Two Dimensions – SS1 Further Mathematics Lesson Note (Second Term)
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- Subject
- Further Mathematics
- Class
- SS1
- Term
- Second Term
- Topic
- Vectors in Two Dimensions
- Order
- Topic 3 of 4 this term
- Reading time
- 1 min
Magnitude of a vector
The magnitude of a vector, sometimes called the modulus of the vector is represented by |a|.
- Zero Vector: The zero vector is a vector with zero magnitude.
- Unit Vector: The unit vector is the vector represented by a and is such that a = |a| a
- Negative Vector: The negative vector of a is written as – a
- Equality of vector: Two vectors are equal when they have the same magnitude and direction.
Example:
Find the modulus of each of the following vectors
- 3i + 4j
- -2i – 5j
Solution
- Let r = 3i + 4j ; then
|r| = ✓(3^2) + (4^2) = ✓25 = 5
2. Let r = -2i – 5j ; then
|r| = ✓(-2^) – (5^2) = ✓4+25 = ✓29
Arithmetic operations on vectors
Example 1:
If p = 2i – 3j; q = 3i + 5j and r = i + j; Find the values of:
- 2p + q + 3r
- 3p – 2q
Solution
- 2p = 2(2i – 3j ) = 4i – 6j
3r = 3( i + j ) = 3i + 3j
Therefore; 2p + q + 3r = (4i – 6j) + (3i + 5j) + (3i + 3j)
= 10i + 2j
2. 3p = 3(3i – 3j) = 9i – 9j
2q = 2(3i + 5j) = 6i + 10j
Therefore 3p – 2q = (9i – 9j) – (6i + 10j) =3i – 19j
Example 2:
Given that OC = a – b and = 2a + 3b, where a = 2i + 3j and b = 3i – 2j, find CD
CD = CO + OD = OD – OC
= (2a + 3b) – (a – b)
= 2a + 3b – a + b = a + 4b
= (2i + 3j) + 4(3i – 2j) = 14i – 5j
This term's Further Mathematics topics
SS1 Second Term · 4 topics


