The Straight Line on Coordinate Geometry SS1 Further Mathematics Lesson Note
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GRADIENT OF A STRAIGHT LINE
The gradient of a straight line is the rate of change of y compared with x.
For example, if the gradient is 2, then for any increase in x, y increases two times as much.
The gradient of AB =
Increase in y from A to B = MB Increase in x from A to B = AM
Example
Find the gradient of the line joining P(7, -2) and Q(-1, 2)
The gradient of PQ =
Increase in y = –AQ
Increase in x PA
= -4 = -1
8 2
Example 2
Find the gradient of the line 7x + 4y – 8 = 0
Re-arrange the equation:
4y = – 7x + 8
y = + 2
Therefore, gradient (m) =
y – 7/4 intercept (c) = 2
SKETCHING GRAPHS OF STRAIGHT LINES
Given the equation: y = 3x – 2, gradient = 3, y-intercept(c) = -2
2x + 3y = 6, gradient = , y-intercept(c) = 2
Example
Sketch the graph of the line whose equation is 4x – 3y = 12
Solution
When x = 0 ,- 3y = 12
y = – 4
The line crosses the y–axis at (0, – 4).
When y = 0 , 4x = 12
x = 3
The line crosses the x-axis at (3, 0).
From the graph:
Gradient m = y2 – y1
x2 – x1 i.e.
0 + 4
3 + 0 y-intercept = – 4
Lines Parallel To Axis
Any line parallel to the x-axis has a gradient of zero. The equation of such lines is always in the form
y = c, where c may be any number.
Draw a graph of y = 5 and y = – 3.
The gradient of a line that is parallel to the y–axis is undefined. The equations of such lines are always in the form x = a, where a may be any number.
The figure will show the graph of lines x = 2 and x = – 4.
Notice that the equation of the y–axis is x = 0
EQUATION OF A STRAIGHT LINE
The equation of a straight line is of the form y = mx + c, where m is the gradient and c is the y-intercept.
Example 1
Determine the equation of a straight line whose gradient is and passes through the point (- 3, 2).
Solution
Using the formula y – y1 = m(x – x1)
Where (x1, y1) = (- 3, 2) and m =
y – 2 = (x + 3)
3y – 6 = – x – 3
x + 3y = 3
EQUATION OF A LINE
The equation of a straight line is given by: y =mx + c
Example: Find the gradient and intercept on the y-axis of the following lines:
y = 3x – 4
y = – ½x – 3
Solution:
Compare y = 3x – 4 with y = mx + c; Hence the gradient is 3, intercept on the y-axis is -4
Gradient is – ½ , intercept on y-axis
GRADIENT AND ONE-POINT FORM
Example: Find the equation of a straight line of slope 2, if it passes through the point (3, -2)
y – y1 = m(x -x1)
m = 2; x1 = 3; y1 = 2
Hence the equation of the straight line is:
y – (-2) = 2(x – 3)
y + 2 = 2x – 6
y = 2x -6 -2 = 2x – 8
y = 2x – 8
ANGLE OF SLOPE
Example: Find the gradient of the line joining (3, 2) and (7, 10) and the angle of slope of the line.
Solution
Let m be the gradient of the line, then
m = 10 – 2 = 8
7 – 3 4
= 2
Let the angle of slope of the line; tan o = 2
= 63.43°